Question

The no load current of a transformer in 5A
at 0.25 power factor when supplied at 235v, 50 Hz
the number of turns on the primary winding is 200. calculate The maximum value of flux in the core.
The core loss and
The magnetizing
component.​

Answer 1

the 1 fig shows the magnaflux and second figure shows the core loss and magnetism components

Answer 2

The maximum value of flux in the core is 4.8412 A .

Step 1: Find the maximum value of flux.

Given - Current $I_0$ = 5A

Power factor = $cos\phi_0$ = 0.25

Number of turns in primary winding = 200

Using formula,

$I_0 = \sqrt{I_M^2 + I_u^2}$

Where , $I_u$ is an active or working component of no-load current and $I_M$ is a magnetizing component of no-load current or flux .

$I_u = I_0cos\phi_0$

$I_u = 5$×$0.25 = 1.25$

$I_0 = \sqrt{I_M^2 + I_u^2}$

$5 =\sqrt{I_M^2 + 1.25^2}$

$25=I_M^2 + 1.5625$

$I_M^2 =25-1.5625$

$I_M^2 = 23.4375$

$I_M=\sqrt{23.4375}$

$I_M= 4.8412\ A$