Question

the no of all naturak nos that lying between 100 and 200 leave remainder 2 when doveded by 5 in each case are​

Answer 1

Answer:

20

Step-by-step explanation:

first no nos that lying between 100 and 200 leave remainder 2 is:

102

so no are

102,107,117,.................197

This is an AP

a=102,d=5,n=? l=197

l=a+(n-1)d

197=102+(n-1)5

(n-1)5=197-102=95

n-1=19

n=20

So no of such numbers are: 20