the no of atoms in 0.1 mol of tetraatomic gas is (Na=6.02×10
Answers
Answered by
1
heya friend!!☺☺
here's your answer!!☺☺
no. of atoms in tetra-atomic gas = 4
no. of gas particles in 1 mole of gas = 6.022* 10^23
thus no. of atoms in 0.1 mol of gas =0.1 * 6.022 *10^23 *4
No. of atoms=24.088×10^22
hope it helps you..!!☺☺
here's your answer!!☺☺
no. of atoms in tetra-atomic gas = 4
no. of gas particles in 1 mole of gas = 6.022* 10^23
thus no. of atoms in 0.1 mol of gas =0.1 * 6.022 *10^23 *4
No. of atoms=24.088×10^22
hope it helps you..!!☺☺
Adityaadidangi:
you didn't multiply 4
Answered by
2
tetraatomic gas contain 4 atoms in one molecule
and in 1mole = 6.023×10²³ molecules
so in 0.1 mole = 6.023×10²²
so no of atoms = 4×6.023×10²²
= 24.092×10²²
or = 2.4092×10²³
hope it helps you
@di
and in 1mole = 6.023×10²³ molecules
so in 0.1 mole = 6.023×10²²
so no of atoms = 4×6.023×10²²
= 24.092×10²²
or = 2.4092×10²³
hope it helps you
@di
Similar questions