The no of atoms in 4.25 g of N3 is
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number of atoms =weight /atomic weight
=4.25/42=0.101 atoms
=4.25/42=0.101 atoms
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molar mass of N3 =14*3=42g
no. of particles in 1g = 6.022*10²³/42
no. of particles in 4.25g =6.022*10²³*4.25/42
no. of particles =6.0936*10²²
no. of particles in 1g = 6.022*10²³/42
no. of particles in 4.25g =6.022*10²³*4.25/42
no. of particles =6.0936*10²²
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