Question

The no.of atoms in 4.25 g of NH3 is approximately

(a) 1 X 1023

(b) 2 X 1023

(c) 4 X 1023

(d) 6 X 1023​

Answer 1

Answer:

So 4.25 g ammonia will contain (6.022×10^23×4.25)/17 = 1.5×10^23 number of ammonia molecules. Each molecule contain 4 atoms (1 N atom and 3 H atoms). So 4.25g ammonia will contain 1.5×10^23×4 = 6×10^23 number of atoms

so your answer is (d)6x 1023

Explanation:

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Answer 2

Explanation:

6.022×10^23 atoms....

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hope you understand