The no. Of atoms of Cr and o are 4.8*10power10 and 9.6 *10 power 10 it's empirical formula is
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We know that the valency of Oxygen is 2 so the oxidation state is -2 Hence let's take the oxidation state of Chromium to be x so
Hence the oxidation state is 4 so one atom of Chromium is oxidised by two atoms of Oxygen so Empirical formula is CrO2. Hope it helps you.
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