The no.of atoms of different elements in 8.5 g of NaNO3 are
Answers
Explanation:
About Sodium Nitrate
About Sodium NitrateThe nitrate anion is a univalent (-1 charge) polyatomic ion composed of a single nitrogen atom ionically bound to three oxygen atoms (Formula: NO3) for a total formula weight of 62.05.
Molecular mass of NaNO₃ = 85 g
Given mass = 8.5 g
Number of moles = Given mass/ molecular mass
Number of moles = 8.5/85
= 0.1 moles
The number of Sodium (Na) atoms present in one mole of NaNO₃
=1 *(6.022×10²³)
The number of Sodium (Na) atoms present in 0.1 mole of NaNO₃
= (0.1×10)= 0.1 *( 6.022×10²³)
The number of Nitrogen (N) atoms present in one mole of NaNO₃
=1 *(6.022×10²³)
The number of Nitrogen (N) atoms present in 0.1 mole of NaNO₃
= (0.1×10)= 0.1 *( 6.022×10²³)
The number of Oxygen (O) atoms present in one mole of NaNO₃
=3 *(6.022×10²³)
The number of Oxygen (O) atoms present in 0.1 moles of NaNO₃
=3 *(6.022×10²³)*0.1= 0.3*(6.022×10²³)