The no of atoms of oxygen present in 11 .2l of ozone at N.T.P are
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Answer:
3.01 x 10²² atoms
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Explanation:
One mole contains = 6.023×10^23 molecules.
One mole = 22.4 liters
6.023×10^23 molecules = 22.4 liters
no of atoms = 3 x no of molecules
= 3.01 x 10²² atoms
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aryan90704410:
wrong
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