Question

The no of atoms that are present in 4.8g of carbon-12 is

Answer 1

mole = GAM/GMM
mole = 4.8/12
mole = 0.4
mole = no.of atoms/Avogadro no.
$0.4 = \frac{no.ofatoms}{ {6.022 \times 10}^{23} }$
$no.ofatoms = {6.022 \times 10}^{23} \times 0.4$
$no.ofatoms = {2.408 \times 10}^{23}$