Question

The no. of boys and girls in a class are in the in the ratio 7:5. The no. of boys is 8 more than the no. of girls. What is the total class strength?​

Answer 1

$\red{\underline{{ \bf Solution }}}$

Let the number of boys be 7x & number of girls be 5x

Now,

Number of boys is 8 more than that of number of girls,

∴ A/q

$\implies \sf 5x + 8 = 7x$

$\implies \sf 5x - 7x = -8$

$\implies \sf -2x = -8$

$\implies \sf -x = \cancel{\dfrac{\cancel{-}8}{\cancel{-}2}}$

$\implies \sf x = 4$

∴ The Value of x ⟹ 4

Number of Boys ⟶ 7x ⟶ 7 × 4 ⟶ 28

Number of Girls ⟶ 5x ⟶ 5 × 4 ⟶ 20

∴ There are 28 boys & 20 girls

⟹ 20 + 28 = 48

∴ Total Strength of the Class is 48

Answer 2

Answer:

48

Step-by-step explanation:

Let the number of boys and girls be 7x and 5x respectively.

Acc. to the question,

=> 7x = 5x + 8

=> 7x - 5x = 8

=> 2x = 8

=> x = 8/2

=> x = 4

So, number of boys = 7x = 28

Number of girls = 5x = 20

Total students = 28 + 20 = 48