The no. of boys and girls in a class are in the ratio 7:5. The no. of boys is 8 more than girls. What is the total class strength?
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Answered by
2
Let the no. of girls be y,
So,
No. of boys = 8+y.
8+y:y=7:5
8+y/y=7/5
On cross multiplication,
40+5y=7y
40= 7y-5y
2y= 40
y=20.
Therefore, no. of boys =28 and no. of girls =20.
Total strength of the class =28+20=48.
Answered by
0
no. of girls be x
no. of boys will be =8+x
now,
7/5=(8+x)/x
7*x=5 (8+x)
x=20
no. of boys will be=8+20=28
total strength wll be=20+28=48
no. of boys will be =8+x
now,
7/5=(8+x)/x
7*x=5 (8+x)
x=20
no. of boys will be=8+20=28
total strength wll be=20+28=48
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