The no of boys and girls in a class in the ratio 7:5. The no of boys in a class is 8 more than the no of girls. What is the total strength?
Answers
Answer:
The no of boys and girls in a class in the ratio 7:5. The no of boys in a class is 8 more than the no of girls. What is the total strength?
Answer: Let the number of boys be 7x and that of girls be 5x.
According to the given condition, we have
Number of boys = Number of girls +8
⇒7x=5x+8
⇒7x−5x=8 ....[Transposing 5x to LHS]
⇒2x=8
⇒x=
2
8
=4
Therefore, number of boys =7×4=28 and number of girls =5×4=20
So, total number of children in the class =28+20=48.
Hence, the class strength is 48.
Step-by-step explanation:
Let the number of boys be 7x and that of girls be 5x.
According to the given condition, we have
Number of boys = Number of girls +8
⇒7x=5x+8
⇒7x−5x=8 ....[Transposing 5x to LHS]
⇒2x=8
⇒x=
2
8
=4
Therefore, number of boys =7×4=28 and number of girls =5×4=20
So, total number of children in the class =28+20=48.
Hence, the class strength is 48.
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