Question

The no. Of carbon atoms in 1.06g of Na2CO3 is?
Please complete explanation
Thank you

Answer 1

please give my ans in brain mark list

Answer 2

Answer:

There are 6.023 × 10²¹ no. of carbon atoms present in 1.06g of Na₂CO₃.

Explanation:

Given,

The weight of Na₂CO₃ (w) is 1.06g.

To find,

The number of Carbon atoms in 1.06 g of Na₂CO₃.

Calculation,

We know that the Gram Molecular weight of Na₂CO₃(G.M.W contains ) is 106g.

So, one mole of Na₂CO₃ weighs 106g. (As 1 mole = 1g of weight/1g of G.M.W)

Hence, 1 mole of Na₂CO₃ i.e. 106g of Na₂CO₃ contains 6.023 × 10²³ carbon atoms.

So, 1.06g of Na₂CO₃ contains:

(1.06g × 6.023 × 10²³atoms)/106g

⇒ 1.06g of Na₂CO₃ contains 6.023 × 10²¹ carbon atoms.

Therefore, there are 6.023 × 10²¹ no. of carbon atoms present in 1.06g of Na₂CO₃.

#SPJ2