Question

The no. Of carbon atoms present in a signature if a signature written by carbon pencil weights 1.2 *10^-3.

Answer 1

Answer:

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Answer 2

Answer:

$6.022 \times 10^{19}$

Explanation:

Moles = $\frac{1.2 \times 10^{-3 \ g} }{12 \ g/mol}$

⇒ $0.1 \times 10^{-3} \ mole$

⇒ $1 \times 10^{-4} \ mole$

Now, we know that $1 \ mole$ has the value of $6.022 \times 10^{23}$ atoms.

Therefore, the number of atoms in $1 \times 10^{-4} \ mole$ will be,

⇒ $6.022 \times 10^{23} \times 1 \times 10^{-4}$

⇒ $6.022 \times 10^{19}$

Final Answer:

The number of atoms in $1 \times 10^{-4} \ mole$ will be $6.022 \times 10^{19}$.

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