Question

- The no. of electrons in 2 gm ion of nitrate ion (NO3 -) is
(a) 64
(b) 64NA
(c) 32
(d) 32NA
Please send a written solution.​

Answer 1

Answer:

$6.4~N_A~electrons.$

Explanation:

Let's first count the no. of electrons in 1 ion of NO₃⁻.

• The "N" atom contains 7 electrons.
• The 3 "O" atoms contain 3 × 8 = 24 electrons.
• And, there's another 1 extra electron on the ion.

Hence, total no. of electrons in 1 ion of NO₃⁻ is 7 + 24 + 1 = 32 electrons.

Now, 0.2 gm ion means 0.2 moles of NO₃⁻.

Since, 1 mole NO₃⁻ contains $N_A$ no. of NO₃⁻ ions

Hence, 0.2 mole NO₃⁻ has $0.2~N_A$ NO₃⁻ ions.

So, total no. of electrons in 0.2 gm ion

$0.2~N_A\times 32~electrons\\\\=6.4~N_A~electrons.$

Hence, correct answer is $6.4~N_A~electrons$, but nothing like this is mentioned in the options. I've let this your typing mistake.

Answer 2

Explanation:

first we find no of electron in nitrate ion (NO3 -)

so,

N=7 , O3=24 ,

7+24=31

now we add 1 ion because it is given in question

so, 31+1=32

Now:-

2g ion of nitrate ,it means 2 mole of nitrate

(now we calculate no of electron 2 ion of nitrate)

2*Na*32=64Na

so, no of electron in 2gm ion of nitrate is :- 64Na