Question

The no. Of electrons in 2gm ion of nitrate NO3 is ?

Answer 1

The no. Of electrons in 2gm ion of nitrate NO3 is 6.17 *10^23

Answer 2

1 Mole of $NO_{3}$ = 55g = $6.022*10^{23}$ molecules
Molecules in 2g od nitrate = $\frac{6.022*10^{23}}{55}*2$ = $2.19*10^{22}$

Valence electrons in one ion (molecule) of $NO_{3}$ = 24
Valence electrons in $2.19*10^{22}$ ions of $NO_{3}$ = $5.256*10^{23}$