Question

The no of families that buy A newspaper only

Answer 1

${ \boxed{ \boxed{ \bold \red{6600}}}}$

Step by Step

Number of families=20000

n(A)=40×20000/100=8000

n(B)=20x20000/100=4000

n(C)=10x20000/100=2000

n(A∩B)=5x20000/100=1000

n(A∩C)=4x20000/100=800

n(B∩C)=3x20000/100=600

n(A∩B∩C)=2x20000/100=400

no. of people buy only A, only B & only C=n(A)-[n(A^B)+n(A^C)-n(A^B^C)]

=8000-(1000+800-400)

=8000-1400

=6600

Answer 2

Answer:

sorry bro I can't do this