Question

the no. of gram equivalent in 5.3 gram of Na2CO3 is?

Answer 1

Molarity = moles of solute ÷ liters of solution 

So since Na2CO3 is the solute, and they give you the grams, just convert to moles: 
(5.3g Na2CO3)(1 mol Na2CO3/105.99g Na2CO3) 
= 0.0500 mol Na2CO3 

Also, the solution has to be in liters, so convert the mL to liters: 
(400.0 mL)(1 L/1000mL) 
= 0.400 L 


Now that you have all of the information, just put it all together into the formula: 
Molarity = moles of solute ÷ liters of solution 
Molarity = (0.0500 mol)/(0.400 L) 
Molarity = 0.125 mol/L or 0.125 M 

Answer 2

it is 0.01grams

hope it help