Chemistry, asked by vvvishalinyvishaliny, 1 year ago

the no of ions present in 1ml of 0.1 M CaCl2 solution is

Answers

Answered by singhmahesh140
30
0.1M solution means that you have 0.1 mol of CaCl2 in 1000mL solution 
But CaCl2 ↔ C+ 2+ + 2Cl- = 3 ions / molecule 
Therefore the 0.1M CaCl2 solution = 0.3M in respect of ions. 

You have 0.3 mol ions in 1000 mL solution 
You have 0.3/1000 = 0.0.0003 mol ions in 1 mL solution 

Number of ions: 
1 mol of ions = 6.022*10^23 ions 
0.0003 mol ions = (0.0003)*(6.022*10^23) = 1.81*10^20 ions.

vvvishalinyvishaliny: thank u
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