Question

the no. of lines that can pass through (3,5) is ​

Answer 1

Step-by-step explanation:

ANSWER

The slope of line joining points (2,5) and (3,6) is m=−3−26−5=−51

We know that, the two non-vertical lines are perpendicular to each other only if and only if their slopes are negative reciprocals of each other.

Therefore, slope of line perpendicular to the line through the points (2,3) and (−3,6)

=−m1=−{5−1}1=5

Now equation of the line passing through points (−3,5) whose slope is 5 is  (y−5)=5(x+3).

⇒y−5=5x+15

⇒5x−y+20=0

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