Question

the no. of mili equivalent of acid in 100 ml of 0.5N solutions is

Answer 1

no.of equivalents= normality*volume(in litre)Therefore,No. Of milliequivalents (n)=normality*volume(in ml)Therefore,n=0.5*100=50

Answer 2

No.of equivalents= normality*volume(in litre)Therefore,No. Of milliequivalents (n)=normality*volume(in ml)Therefore,n=0.5*100=50