Question

the no.of millimoles of HCl required to neutralize 10ml of 0.2M Na2CO3 is​

Answer 1

Answer:

0.000004

Explanation:

Before we tackle this question we must first know that 1 mole is equivalent to 1000 millimoles

We must then write a balanced chemical equation

2HCl + Na2CO3 –> 2NaCl + CO2 + H2O

Since we have the volume and molarity of Na2CO3 we can find its moles

one centimetre cubic is the same as one millilitre hence 10cm3 of volume

If 0.2 moles– 1000 cm3

        ?      –     10cm3

We multiply 0.2× 10÷1000 = 0.002 moles

The mole ratio of HCl to Na2CO3 is 2:1

We therefore multiply the moles we have found by 2 to get the moles of HCl

0.002 × 2 = 0.004 moles of HCl

After that we divide the moles of HCl with 1000 to get the millimoles

0.004 ÷ 1000 = 0.000004 millimoles

Answer 2

Explanation:

here's your answer

0.000004 milimoles

hope this helps you