Question

The no. Of molecule in 100ml of 0.02N H2so4 is

Answer 1

H2SO4 → SO42- + 2H+

Since one mole of H2SO4 = 2 moles equivalents of H+

Therefore, molarity = normality/2

                                    = 0.01 M  

Now, 0.01M = 0.01=no. of moles of H2SO4×1000Volume of solution in mlOrNo of moles=0.01×100 1000=0.001 mol

We know that 

No of molecules in one mole = 6.022×1023

Therefore, no of molecules in 0.001 mol = 0.001​×6.022​×1023, i.e 0.006 ​×1023molecules.

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Answer 2

Hey, dear your answer is here.


H2SO4 → SO42- + 2H+
Since one mole of H2SO4 = 2 moles equivalents of H+
Therefore, molarity = normality/2
                                    = 0.01 M  
Now, 0.01M = 0.01=no. of moles of H2SO4×1000Volume of solution in mlOrNo of moles=0.01×100 1000=0.001 mol

We know that 
No of molecules in one mole = 6.022×1023
Therefore, no of molecules in 0.001 mol = 0.001​×6.022​×1023, i.e 0.006 ​×1023molecules.

I think it will help you dear.