Question

The no of molecule in 22.4 cm3 nirogen gas at stp is

Answer 1

1 cm^3 = 1 ml 22.4 cm^3 = 22.4 ml 22.4 ml = 22.4*10^-3 litres  No. of moles in 22.4*10^-3 litres = 22.4*10^-3 / 22.4  = 0.001 moles   No. of molecules in 0.001 moles of Nitrogen gas = 0.001 * 6.022*10^23 = 6.022 * 10^20   Answer = 6.022 * 10^20