English, asked by pujadui1415, 7 months ago

( The no.
of molecule present in one drop (0.05ml)of benzene (density =0.78g/ml) is nearly equal to
(NA = 6*1023)

Answers

Answered by SimranPanda
0

Answer:

Mass of 1 drop of benzene =0.05×0.78=0.039g

Moles of benzene =  

78

0.039

​  

=5×10  

−4

 

1 mole of benzene contains 6×10  

23

 molecules.

∴ Molecules present in 1 drop =5×10  

−4

×6×10  

23

=3×10  

20

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