( The no.
of molecule present in one drop (0.05ml)of benzene (density =0.78g/ml) is nearly equal to
(NA = 6*1023)
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Answer:
Mass of 1 drop of benzene =0.05×0.78=0.039g
Moles of benzene =
78
0.039
=5×10
−4
1 mole of benzene contains 6×10
23
molecules.
∴ Molecules present in 1 drop =5×10
−4
×6×10
23
=3×10
20
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