Question

The no. of nitrogen atoms in 28 grams of nitrogrn gas is how much? ​

Answer 1

Answer:

2×6.022×$10^{23}$

Explanation:

Answer 2

Answer:

2*6.022*10²³

Explanation:

the no of N2 molecules in 28 g is 6.022*10²³ so the no of N atoms is just double the no of N2 molecules..