Question

The No.of oxygen atoms present in 60g of glucose

Answer 1

The formula of glucose : C6H12O6.
Molecular mass: 180g
Now,
In 180g glucose, there are 6 × 6.023 × 10^23 oxygen atoms.
In 1 g glucose, there are (6 × 6.023 × 10^23)/180 oxygen atoms.
In 1.80 g glucose, there are {(6 × 6.023 × 10^23)/180} × 1.80 oxygen atoms.
It comes to be...
0.36138 × 10^23 oxygen atoms.

Answer 2

$\textbf{ANSWER}$

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$\textbf{GIVEN}$

Mass of glucose =60g

Moles of glucose = mass/molar mass

Moles of glucose = 60/180

Moles of glucose = 0.33mol

Number of atoms of oxygen = number of atoms of oxygen in 1 molecule of glucose × moles of glucose × avagadro numer

Number of atoms of oxygen = 6 × 0.33× 6.023×10^23

Number of atoms of oxygen =11.9×10^23
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