Question

the no. of particles scattered at 60° is 100 per min in a alpha scattering experiment using gold foil. claculate the no. of particles per min scattered at 90° angle​

Answer 1

Answer:

Explanation:

t can be shown that number of particles N scattered per unit area at an angle θ is directly propotional to 1sin4(θ/2)

∴N2N1=[sinθ1/2sinθ2/2]4

N2100=(sin60∘/2)4(sin90∘/2)4=(sin30∘)4(sin45∘)4=(1/2)4(1/2–√)4=14

N2=1004=25

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