Chemistry, asked by raniyamohmed, 11 months ago

The no of photons emitted in one second by 10W bulb which emits monochromatic light of wavelength 662nm is

Answers

Answered by ankitsunny
2

Explanation:

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Answered by mohsinjavied
1

Answer:

3.3×10^17

Explanation:

E=hc/wavelength

  1. E= 6.63×10^-34Js×3×10^8ms^-1 ÷ 662×10^-9 m. =3.0×10^-17J
  2. 10W = 10Js^-1

3. number of photos n= 10÷ 3.0×10^-17

4. n=3.0×10^17 answer

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