The no of polynomials having zeros as _2and5i is
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Answered by
0
Answer:
infinitely many solution is the answer
Answered by
1
Answer:
Xsquare +2x+5
Step-by-step explanation:
Let
Alfa + Beta = - 2
Nd alfa * beta = 5
Then formula =
Xsquare - (alfa+Beta)x + (alfa*beta)
Substuting
Xsquare - (-2)x + (5)
Thus= xsquare + 2x + 5
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