Question

the no of real value of x satisfying the equation (x-4)^2 +(28-6x)^3=1 is

Answer 1

(x

2

−5x+5)

x

2

+4x−60

=1

First possibility is x

2

+4x−60=0

x=−10,6

Seond possibility is x

2

−5x+5=1

x=1,4

Third Possibility

x

2

−5x+5=−1

x=2,3

substitute x=3 it will give odd number in x

2

+4x−60

So x=2 is only acceptable.

Sum of the integers =−10+4+1+6+2=3