Question

the no. of revolutions per second around the nucleus in 3rd bohr orbit
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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

From Bohr's theory

mvr=

2π

nh

For first orbit n=1

m(rω)r=

2π

1×h

⇒mr

2

2πf=

2π

h

⇒f=

4π

2

mv

2

h

=

4×(3.14)

2

×9.1×10

−31

×(0.33×10

−10

)

2

6.6×10

−34

.

=6.5×10

15

Hz

Explanation:

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