Question

The no. Of water molecules present in a drop of water weighing 0.05 mg is

Answer 1

Answer:

we know the formulae:-

N= m * 6.023*10^23

so first convert 0.05mg to g which is 5/1000g

now finding moles:-

moles= given mass/atomic mass

now,

N= 90/1000 * 6.023*10^23

N is your answer