Question

The no of ways in which 12 students can be equally divided into 3 groups is

Answer 1

Here is your answer buddy,

Let,

12 students are (A, B, C, D, E, F, G, H, I, J, K, L)

So,

1st group (A, B, C, D) = 12 - 4 = 8.

2nd group (E, F, G, H) = 8 - 4 = 4

3rd group (I, J, K, L) = 4 - 4 = 0

Now,

Every group has 4 students.

Therefore,

12C4 × 8C4 × 4C4
=( 12!/4! × 8! ) × ( 8!/4! × 4!) × (4!/4! × 0!)

As we knew,

[ nCr = n! /(n-r)! × r! ]

= 495 × 70 × 1
= 34650

Now, 34650/3! = 5775 .

Hope this helps you.
Be Brainly.