Question

The no of ways in which 5 girls and 3 boys can be seated in arow.With no.Two.Boys are together

Answer 1

Answer:

For any one seating arrangement the number of permutations is

5! * 3! = 720

Now consider the arrangement

GGBGBGBG and change it to GBGGBGBG and then

GBGBGGBG and finally GBGBGBGG

So there are 4 such arrangements and the total number of ways is

4 * 720 = 2880