The no. of zeros at the end of (2^123 - 2^122 -2^121)(3^ 223 - 3^222 - 3^221) is:
A) 0
B) 1
C) 2
D) 3
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Hey mate,
Your answer is option 'A' explanation as to get zero we have to multiply a multiple of 2 with a multiple of 5 , in above's case we are only able to get multiple of 2 but not of 5 so there should not be any zero at the end .
Your answer is option 'A' explanation as to get zero we have to multiply a multiple of 2 with a multiple of 5 , in above's case we are only able to get multiple of 2 but not of 5 so there should not be any zero at the end .
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