the no. x is 2 more than no. y.If the sum of the squares of x and y is 34,then find the product of x and y.
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x=y+2
x²+y²=34
(y+2)²+y²=34
y²+4+4y+y²=34
2y²+4y+4=34
y²+2y+2=17
y²+2y=15
y²+2y-15=0
y²+5y-3y-15=0
y(y+5)-3(y+5)=0
(y-3)(y+5)=0
∴ y=3
y= -5
x=y+2
1st case:
x=3+2
x=5
2nd case
x= -5+2
x= -3
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