Question

the nominator of rational number is less than its denominator by 3 if the nominated becomes three time and the denominator is increased by 20 the new number become 1 by 8 find the original number.​

Answer 1

❍  Given that, the numerator of rational number is less than its denominator by 3 if the numerator becomes three times and the denominator is increased by 20 the new number become 1 by 8.  

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• Let the denominator the rational number be ‘ x ’  

• Then the numerator will be ‘ x - 3 ’

 

~The equation formed according to the question is ::  

$\sf \bullet \;\; \dfrac{(x-3) \times 3}{ x + 20} = \dfrac{1}{8}$

$\sf : \; \implies \dfrac{( x \times 3)- ( 3 \times 3)}{x + 20} = \dfrac{1}{8}$

$\sf : \; \implies \dfrac{3x-9}{x+20} = \dfrac{1}{8}$

$\bf \; \maltese \;\; cross \; multiply$

$\sf : \; \implies 8( 3x -9) = 1( x + 20)$

$\sf : \; \implies 24x -72 = x + 20$

$\sf : \; \implies 24x -x = 20 + 72$

$\sf : \; \implies 23x = 92$

$\sf : \; \implies x = \dfrac{92}{23}$

$\sf : \; \implies x = 4$

T H E R E F O R E ,  

$\sf : \; \implies \dfrac{x-3}{x}$

$\sf : \; \implies \dfrac{4-3}{4}$

$\sf : \; \implies \dfrac{1}{4}$

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• Henceforth, the rational number is 1/4

Answer 2

Answer of the above mentioned।