Question

The non negetive real zero of quadratic polynomial 3x2-5x-2

Answer 1

Answer:

3x^2-5x-2 =0

=> 3x^2-6x+x-2=0

=> 3x(x-2) +1(x-2)=0

=> (3x+1)(x-2)=0

thus x=2,-1/3

but we required non negative zero

hence

x=2 is the only solution of the polynomial

hope this will helpful to you

Answer 2

The non negetive real zero of quadratic polynomial 3x² - 5x - 2 is 2

Given :

The quadratic polynomial 3x² - 5x - 2

To find :

The non negetive real zero of the quadratic polynomial 3x² - 5x - 2

Solution :

Step 1 of 3 :

Write down the given Quadratic polynomial

Here the given quadratic polynomial is 3x² - 5x - 2

Step 2 of 3 :

Find zeroes of the quadratic polynomial

For Zeroes of the quadratic polynomial 3x² - 5x - 2 we have

$\displaystyle \sf{ 3{x}^{2} - 5x - 2 = 0 }$

$\displaystyle \sf{ \implies 3{x}^{2} - ( 6 - 1)x - 2 = 0}$

$\displaystyle \sf{ \implies 3{x}^{2} -6 x + x - 2 = 0}$

$\displaystyle \sf{ \implies 3x(x - 2) + 1(x - 2) = 0}$

$\displaystyle \sf{ \implies (x - 2) (3x + 1) = 0}$

$\displaystyle \sf{ \implies x =2 \:, \: - \frac{1}{3} }$

So the zeroes of the quadratic polynomial are 2 , - 1/3

Step 3 of 3 :

Find the non negetive real zero of quadratic polynomial

The Zeroes of the quadratic polynomial 3x² - 5x - 2 are 2 , - 1/3

Now - 1/3 is negative

Hence non negetive real zero of quadratic polynomial 3x² - 5x - 2 is 2

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