Question

the non parallel sides of an isosceles trapezium are 12 cm each. if the perimeter of that trapezium is 56 cm and height is 7 cm, then the area of that trapezium is what​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Image.

we know attitude is also a median in equilateral triangle.

BG = GC = 3 cm.

from ΔABG by Pythagoras theorem.

(AB)

2

=(AG)

2

+(BG)

2

(6)

2

=(AG)

2

+(3)

2

(AG)=

36−9

AG=

27

=5.20cm.

Height of trapezium = 2.60 cm → (given in question ⇒

2

5.20

=2.60cm)

Area of trapezium -

2

(a+b)×h

=

2

(6+3)×2.60

=9×

Step-by-step explanation:

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