The normal density of gold is p its bilk moduls is k.The increase of density of a
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Hii dear,
● Answer - ρK/P
● Solution-
Lets assume P be the pressure applied on the gold lump.
strain = ∆V / V
stress = P
K = stress / strain
K = P / (∆V/V)
K = PV / ∆V
Putting V = M/ρ, ∆V = M/∆ρ -
K = P (M/ρ) / (M/∆ρ)
K = P × ∆ρ / ρ
∆p = ρK/P
Change in density ia ρK/P.
Hope this is uzeful...
● Answer - ρK/P
● Solution-
Lets assume P be the pressure applied on the gold lump.
strain = ∆V / V
stress = P
K = stress / strain
K = P / (∆V/V)
K = PV / ∆V
Putting V = M/ρ, ∆V = M/∆ρ -
K = P (M/ρ) / (M/∆ρ)
K = P × ∆ρ / ρ
∆p = ρK/P
Change in density ia ρK/P.
Hope this is uzeful...
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