Question

The normal density of gold is rho and its bulk modulus is k. The increase in density of a lump of gold when a pressure p is applied uniformly on all sides is

Answer 1

As,

K = -V d P / d V

In this case, if mass remains constant ,

d V / V = d ρ / ρ

So, we get :

K = - ρ d P / d ρ

d P = P

And we get by this:

d ρ = - ρ P / K

Answer 2

Answer:

Explanation:

I hope it helps