Physics, asked by vithya01, 11 months ago

the normal force applied by block on the ground is ​

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Answered by ayush9984
1
  • Explanation:

in the box mg is applied in downwards direction,and cos(theeta) components of force f is responsible for force on ground

mg and f cos are in opposite direction

hence

mg-fcos(theeta)

may be correct

to solve this type of problem first make FBD

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