Math, asked by PSSMBSAI248, 1 day ago

The normal to a circle S=OatP(1.3) is x2 7 and it has another normal at Q3.5) whichi the polar of the point A 7- with respect the circle x + y - 4x + y - 12 = 0. Then the equation of the circle S=0 is ​

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Answered by mohdkaleem5812
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The normal to a circle S=OatP(1.3) is x2 7 and it has another normal at Q3.5) whichi the polar of the point A 7- with respect the circle x + y - 4x + y - 12 = 0. Then the equation of the circle S=0 is

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