Question

The normality if 0.1 M phosphoric acid is??

Answer 1

Answer:

0.3N

Explanation:

Normality =molarity×n -factor  

And for any phosphorus containing  

acid ,n-factor =(no.of o-atoms-1)=(4-1)

=3.

Molarity =0.1M

NORMALITY=0.1×3=0.3N

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Answer 2

Answer: normality = molarity * n-factor

Explanation: so

N-factor of phpsphoric acid is three

Normality=0.1*3=0.3 ur answer is here!!!!