the normality if a solution obtained by mixing 100 ml of 0.2 N HCL and 500 ml if 0.12 M H2So4 is
Answers
Answer:
- The Normality (N) is 0.033 N
Given:
- 100 ml of 0.2 N HCl
- 500 ml of 0.12 M H₂SO₄
Explanation:
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Firstly let's find the Molarity of HCl.
From the formula we know,
⇒ M = N × V
Here,
- M Denotes Molarity.
- N Denotes Normality.
- V Denotes volume.
Substituting the values,
⇒ M₁ = 0.2 N × 100 ml
⇒ M₁ = 0.2 × 100
⇒ M₁ = 20
⇒ M₁ = 20 M
∴ Molarity of HCl solution is 20 M.
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Let's find the Total molarity of the solution and Total volume of the solution.
Total Molarity:
Since all components have same nature i.e. acidic nature. the equivalent Molarity will be sum of the two molarity given.
Therefore,
⇒ M = M₁ + M₂
Substituting the values,
⇒ M = 20 + 0.12
⇒ M = 20.12
⇒ M = 20.12 M
∴ Molarity of total solution is 20.12 M.
Total Volume:
⇒ V = V₁ + V₂
Substituting the values,
⇒ V = 100 + 500
⇒ V = 600
⇒ V = 600 ml
∴ Total volume of the solution is 600 ml.
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Now, let's find the normality of resultant solution.
⇒ N = M / V
Here,
- M Denotes Molarity.
- N Denotes Normality.
- V Denotes volume.
Substituting the values,
⇒ N = 20.12 / 600
⇒ N = 0.033
⇒ N = 0.033 N
∴ The Normality (N) of the solution is 0.033 N.
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