the normality of 0.3 mole of h 3 PO 4 is
YashParitkar:
It should me molarity.
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Normality * equivalent mass = Molarity * molar mass
N = (0.3 * 98) / (98 / 3)
= 0.901
N = (0.3 * 98) / (98 / 3)
= 0.901
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Explanation:
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