The normality of 0.3M phosphorous acid (H3P03) is
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As you should know, /=
N factor for an acid is its basicity, or number of replaceable H+ ions in one molecule of the acid
If you look at its structure, there are only 2 acidic hydrogens in it. One hydrogen is directly attached to phosphorus, it is not acidic
So you answer will be 0.3 (Molarity) * 2 (n factor) = 0.6 N
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