Chemistry, asked by bvrcraobodduluri, 1 month ago

The normality of 10% (weight/volume)
acetic acid is
(A) IN
(B) 10 N
(C) 17 N
(D) 0.83 N​

Answers

Answered by nirmalyarishi
0

Answer:

b)

Explanation:

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Answered by Rajkd180203
0

Answer:

1.67 N is the normality of acetic acid

Explanation:

Normality (N) is defined as number of gram equivalents of solute present in one liter of solution.

Normality =  gram equivalent/ volume of solution

From the given , 10% w/v acetic acid means 10 grams of acetic acid is dissolved in 100 ml of water.

Molar mass of acetic acid = 60 .05 g/mol

Per 1000 ml of solution has 100 g of solute = 100/60.05 = 1.665

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