the normality of a solution of sodium hydroxide 100 ml of which contains 4 gram of NaOH
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The normality of solution of sodium hydroxide (NaOH) is equal to 1N.
Explanation:
We have given, the mass of sodium hydroxide = 4 grams
Volume of sodium hydroxide solution = 100ml = 0.1L
The molecular mass of sodium hydroxide = 23 + 1 + 16 = 40g/mol
The n- factor of NaOH = number of OH⁻ ions = 1
Therefore, equivalent weight of NaOH = 40/1 = 40eq
Number of gram equivalents = Mass of NaOH/ equivalent mass
= 4/40 = 0.1 g/eq
Normality of NaOH solution = No. of gram equivalents/ Volume (in L)
Therefore, the normality of sodium hydroxide solution is 1N.
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